Web2 moles of an ideal gas A ( C P =4R) and 4 moles of an ideal gas B ( C V = 23R) are taken together in a container and allowed to expand reversibly and adiabatically from 49L to 64L, starting from an initial temperature of 47 0 C. The final temperature of the gas is : Hard View solution > View more Get the Free Answr app Web16. (Kinetic energy of gases) For two gases A and B, the average kinetic energy is the same at a given temperature: Compared to lighter atoms at the same temperature, …

The relative the rate of diffusion of two gases A and B are found …

WebA mixture of two gases A and B in the mole ratio 2: 3 is kept in a 2 litres vessel. A second 3 litres vessel has the same gases in the mole ratio 3: 5.Both gas mixtures have the same temperature and same total pressure. They are allowed to intermix and the final temperature and total pressure are the same as the initial values, the final volume being 5 litres. WebCorrect option is B) For adiabatic processes, PV γ= constant When Pressure decrease, Volume has to increase to maintain the above relation. Even as Volume increases, the increase is volume would be higher when the exponent γ has a lower value than when the value of γ is higher. fe ch3coo 2 · 4h2o

Dalton

WebP-V plots for two gases during adiabatic process are shown in the figure. Plots 1 and 2 should respectively correspond to A He and O2 B O2 and He C He and Ar D O2 and N 2 Solution The correct option is B O2 and He In adiabatic process, P V γ =constant For a monoatomic gas, γ =Cp/Cv =1.67 For a diatomic gas. γ =1.4 WebThe partial pressure of a gas can be calculated using the ideal gas law, which we will cover in the next section, as well as using Dalton's law of partial pressures. Example 1: Calculating the partial pressure of a gas … WebFor two gases A and B with molecular weights M A and M B, respectively, it is observed that at a certain temperature T, the mean velocity of A is equal to the V rms of B. Thus, … fe ch3cooh